How can I invoke streamlit from within python code?

Hello Folks,

What is the best means to invoke streamlit from within python code ?
I dont want to go via the CLI route of streamlit run <>

This link has some reference, but again to invoke as mentioned in link, python click context is needed.


Looks like this is a way:

import os
import streamlit.bootstrap
from streamlit import config as _config

dirname = os.path.dirname(__file__)
filename = os.path.join(dirname, '')

_config.set_option("server.headless", True)
args = []

#streamlit.cli.main_run(filename, args),'',args)

Thanks for the helpful tips! That’s what I was trying to find.

By the way, when I ran your code, I saw the following error.

TypeError: run() missing 1 required positional argument: 'flag_options'

Instead, I had to write as following. This may be due to a different version of Streamlit. (I’m using Streamlit version 0.86.0.), '', args, flag_options={})

In anyway, thanks again for the tips!


Hi, i figured when i start streamlit with bootstrap, it will break forms. As long as I run the code from command line, everything works. When I invoke streamlit from within python, forms are broken.

I opened an issue here.

Feel free to add if you have any thoughts about it.